Hydrogen Fluoride Urea complex synthesis

Yield:24926-15-6 25%

Reaction Conditions:

with hydrogen fluoride at -25 - 20; for 2.33333 h;Large scale;

Steps:

1 Example 1

In the volume of 200L, with sandwich, Teflon-lined reactor top fixed backAnd the sandwich layer of the reaction kettle is filled with the condensate, and the sandwich layer and the condensing tube are shared by one setRefrigerator, open the refrigerator, slowly to the reactor by adding 20kg anhydrous hydrogen fluoride, control the anti-Should be inside the temperature of -25 , and then slowly to the reactor by adding 60kg of urea, control reactorThe internal temperature of -15 , continue stirring reaction 20min, turn off the refrigerator, the reactor temperatureHeating to room temperature, room temperature reaction 2h, which was containing hydrogen fluoride mass percentage of 39.8%Hydrogen fluoride urea of the formula CH4N2O · HF.The resulting hydrogen fluoride hydrate was a white solid,The yield was 25.0%.

References:

CN105693557,2016,A Location in patent:Paragraph 0019; 0020; 0021